(2x^2-3x+5)(4x-1)=

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Solution for (2x^2-3x+5)(4x-1)= equation: 


Simplifying
(2x2 + -3x + 5)(4x + -1) = 0

Reorder the terms:
(5 + -3x + 2x2)(4x + -1) = 0

Reorder the terms:
(5 + -3x + 2x2)(-1 + 4x) = 0

Multiply (5 + -3x + 2x2) * (-1 + 4x)
(5(-1 + 4x) + -3x * (-1 + 4x) + 2x2 * (-1 + 4x)) = 0
((-1 * 5 + 4x * 5) + -3x * (-1 + 4x) + 2x2 * (-1 + 4x)) = 0
((-5 + 20x) + -3x * (-1 + 4x) + 2x2 * (-1 + 4x)) = 0
(-5 + 20x + (-1 * -3x + 4x * -3x) + 2x2 * (-1 + 4x)) = 0
(-5 + 20x + (3x + -12x2) + 2x2 * (-1 + 4x)) = 0
(-5 + 20x + 3x + -12x2 + (-1 * 2x2 + 4x * 2x2)) = 0
(-5 + 20x + 3x + -12x2 + (-2x2 + 8x3)) = 0

Combine like terms: 20x + 3x = 23x
(-5 + 23x + -12x2 + -2x2 + 8x3) = 0

Combine like terms: -12x2 + -2x2 = -14x2
(-5 + 23x + -14x2 + 8x3) = 0

Solving
-5 + 23x + -14x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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